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[文件操作] 批处理代码一个字符替换两行代码

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发表于 2012-7-19 10:38:02 | 显示全部楼层 |阅读模式
本帖最后由 wangxiulin 于 2012-7-19 10:47 编辑
  1. @echo off
  2. (For /f "delims=" %%i in (a.txt) do (Set str=%%i
  3. SetLocal EnableDelayedExpansion
  4. Set str=!Str:MoveTo=SetCursorPos!
  5. Set str=!Str:RightDown 1=mouse_event MOUSEEVENTF_RIGHTDOWN, 0, 0, 0, !
  6. echo !str!
  7. EndLocal
  8. ))>1.txt
  9. start 1.txt
  10. pause>nul
复制代码
这个是讲MoveTo 替换 SetCursorPos
RightDown 1 替换  mouse_event MOUSEEVENTF_RIGHTDOWN, 0, 0, 0,

怎么让 RightDown 1 替换
mouse_event MOUSEEVENTF_RIGHTDOWN, 0, 0, 0,  0
mouse_event11111 MOUSEEVENTF_RIGHTDOWN, 0, 0, 0, 0

让他替换成这两句。怎么替换?
发表于 2012-7-19 10:51:38 | 显示全部楼层
Set fso = CreateObject("Scripting.FileSystemObject")
word = fso.OpenTextFile(
"a.txt").ReadAll
word = Replace(word,
"MoveTo","SetCursorPos")
word = Replace(word,
"RightDown 1","mouse_event MOUSEEVENTF_RIGHTDOWN, 0, 0, 0, 0" & vbCrLf & "mouse_event11111 MOUSEEVENTF_RIGHTDOWN, 0, 0, 0, 0")
fso.OpenTextFile(
"ok.txt",2,1).Write word
MsgBox
"OK"


我只会VBS的,你试试、、
 楼主| 发表于 2012-7-19 10:56:03 | 显示全部楼层
回复 2# 乱码


    不管bat 还是 vbs 能用就行..测试可以..谢谢乱码了..
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