回复 3# 5i365 - [code]$a = '$para.Format.BeforeSpacing = 8.2f
- $para.Format.AfterSpacing = 16.22f
- $para.Format.LineSpacing = 136.6f
- "abc 15.5f56"
- $paragraph.Format.BeforeSpacing -eq 6f -and $paragraph.Format.AfterSpacing -eq 6.54f -and $paragraph.Format.LineSpacing -eq 12f'
- $a -creplace '( \d+\.?\d*?)f(\r\n)?(?![\w])','$1'
复制代码 [/code] |