terse

回复 40# xxpinqz
再仔细回看前面 猜真这次应该理解了
先粗糙一个
感觉代码写得太啰嗦   等下再看有 优化的可能不

@echo off&setlocal enabledelayedexpansion
%1 %0 REM|more /t32 >n.txt
set L=5
set "file=a1.txt"
for /f "delims=U" %%a in ('cmd /u /c echo 唉') do set "tab=%%a"
for /f "usebackq tokens=*" %%i in ("%file%") do set /a N+=1&set #!N!=%%i
set /a h=(n+l-1)/l,j=n,i=1
if !h! lss !l! set /a j=(n%%l)*H
for /l %%i in (1 1 %n%) do (
    set /a "t=^!^!(~-%%i/j)"
    set /a "m=(~-%%i-(t*j))%%(~-H+i*^!t)+1"
    for %%j in (!m!) do set "$%%j=!$%%j!%tab%!#%%i!"
)
for /l %%i in (1 1 %h%) do for /f "tokens=*" %%j in ("!$%%i!") do echo %%j
复制代码

terse

唉 惭愧我的理解力  但楼主的表达也太那个了  
都和我一样 国语学得不好

terse

你是指最后的回车行是MORE留下的吧
代码再少点变量
另补上exit

@echo off&setlocal enabledelayedexpansion
%1 %0 :|more /t32 >n.txt&exit
set L=9
set "file=a.txt"
for /f "delims=U" %%a in ('cmd /u /c echo 唉') do set "tab=%%a"
for /f "usebackq tokens=*" %%i in ("%file%") do set /a N+=1&set #!N!=%%i
set /a h=(n+l-1)/l,j=n
if !h! lss !l! set /a j=(n%%l)*h 
for /l %%i in (1 1 %n%) do (
    set /a "i=^!(~-%%i/j),m=(~-%%i-(^!i*j))%%(~-H+i)+1"
    for %%j in (!m!) do set "$%%j=!$%%j!%tab%!#%%i!"
)
for /l %%i in (1 1 %h%) do for /f "tokens=*" %%j in ("!$%%i!") do echo %%j
复制代码

terse

回复 30# pan528
也许代码的算法有误
这样吧 你把44楼代码里  if !h! lss !l! set /a j=(n%%l)*h 这里的 LSS 改为GTR 看是否你要的

@echo off&setlocal enabledelayedexpansion
%1 %0 :|more /t32 >n.txt&exit
set L=9
set "file=test.txt"
for /f "delims=U" %%a in ('cmd /u /c echo 唉') do set "tab=%%a"
for /f "usebackq tokens=*" %%i in ("%file%") do set /a N+=1&set #!N!=%%i
set /a h=(n+l-1)/l
if !h! gtr !l! set /a j=(n%%l)*h
if !j! equ 0 set j=!n!
for /l %%i in (1 1 %n%) do (
    set /a "i=^!(~-%%i/j),m=(~-%%i-(^!i*j))%%(~-H+i)+1"
    for %%j in (!m!) do set "$%%j=!$%%j!%tab%!#%%i!"
)
for /l %%i in (1 1 %h%) do for /f "tokens=*" %%j in ("!$%%i!") do echo %%j
复制代码

代码处理流程是这样的
当行大于列 或 行小于列时的输出是不一样的

terse

有点给数字绕晕的感觉
只能再试着简化下 思路闭塞 总不能突破

@echo off&setlocal enabledelayedexpansion
%1 %0 :|more /t32 >n.txt&exit
set "file=test.txt"
for /f "delims=U" %%a in ('cmd /u /c echo 唉') do set "tab=%%a"
for /f "usebackq tokens=*" %%i in ("%file%") do set /a N+=1&set #!N!=%%i
set L=9
set /a "h=(n+l-1)/l,i=^!(~-l/h),j=^!i*(n%%l)*h+i*n"
for /l %%i in (1 1 !n!) do (
    set /a "i=^!(~-%%i/j),m=(~-%%i-(^!i*j))%%(~-h+i)+1"
    for %%j in (!m!) do set "$%%j=!$%%j!%tab%!#%%i!"
)
for /l %%i in (1 1 !h!) do for /f "tokens=*" %%j in ("!$%%i!") do echo %%j
复制代码

既然MORE 最后回车肯定有 没必要再处理它了吧

@echo off&setlocal enabledelayedexpansion
%1 %0 :|more /t32 >n.txt&exit
set "file=test.txt"
for /f "delims=U" %%a in ('cmd /u /c echo 唉') do set "tab=%%a"
for /f "usebackq tokens=*" %%i in ("%file%") do set /a N+=1&set #!N!=%%i
set L=9
set /a "h=(n+l-1)/l,j=n%%l,i=^!(l/h)"
if !j! equ 0 (set j=!n!)else set /a "j=~-l*h*i+j*h" 
for /l %%i in (1 1 !n!) do (
    set /a "i=^!(~-%%i/j),m=(~-%%i-(^!i*j))%%(~-h+i)+1"
    for %%j in (!m!) do set "$%%j=!$%%j!%tab%!#%%i!"
)
for /l %%i in (1 1 !h!) do for /f "tokens=*" %%j in ("!$%%i!") do echo %%j
复制代码

terse

不是列大于行 3分吗
余数: 34/9 应该余7  7大于行4啊
这里的余数是否 应该  34/4 余 2 ？

你30楼的描述

..三分法就是：在上面二分法的基础上，对切分列数小于每列行数的情形，用另一种方法排列，即把所有空格放在最后一列。...