plp626

回复 3# JooKin

->for /l %a in (-15 1 15)do d2b %a

->d2b -15
11111111111111111111111111110001

->d2b -14
11111111111111111111111111110010

->d2b -13
11111111111111111111111111110011

->d2b -12
11111111111111111111111111110100

->d2b -11
11111111111111111111111111110101

->d2b -10
11111111111111111111111111110110

->d2b -9
11111111111111111111111111110111

->d2b -8
11111111111111111111111111111000

->d2b -7
11111111111111111111111111111001

->d2b -6
11111111111111111111111111111010

->d2b -5
11111111111111111111111111111011

->d2b -4
11111111111111111111111111111100

->d2b -3
11111111111111111111111111111101

->d2b -2
11111111111111111111111111111110

->d2b -1
11111111111111111111111111111111

->d2b 0
00000000000000000000000000000000

->d2b 1
00000000000000000000000000000001

->d2b 2
00000000000000000000000000000010

->d2b 3
00000000000000000000000000000011

->d2b 4
00000000000000000000000000000100

->d2b 5
00000000000000000000000000000101

->d2b 6
00000000000000000000000000000110

->d2b 7
00000000000000000000000000000111

->d2b 8
00000000000000000000000000001000

->d2b 9
00000000000000000000000000001001

->d2b 10
00000000000000000000000000001010

->d2b 11
00000000000000000000000000001011

->d2b 12
00000000000000000000000000001100

->d2b 13
00000000000000000000000000001101

->d2b 14
00000000000000000000000000001110

->d2b 15
00000000000000000000000000001111

->
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plp626

回复 5# JooKin


    cmd的数字是有符号数，按理是算术移位

->d2b -1

11111111111111111111111111111111

->d2b 0

00000000000000000000000000000000

->d2b 1

00000000000000000000000000000001
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plp626

回复 8# JooKin

>> set/a 2147483647
2147483647
>> set/a 2147483648
-2147483648
>> set/a 2147483649
-2147483647
>> set/a 4294967294
-2
>> set/a 4294967295
-1
>> d2b 2147483647
01111111111111111111111111111111
>> d2b 2147483648
10000000000000000000000000000000
>> d2b -2147483648
10000000000000000000000000000000
>> d2b 2147483649
10000000000000000000000000000001
>> d2b -2147483647
10000000000000000000000000000001
>> d2b 4294967294
11111111111111111111111111111110
>> d2b -2
11111111111111111111111111111110
>> d2b 4294967295
11111111111111111111111111111111
>> d2b -1
11111111111111111111111111111111
>> set/a -1/4294967295
1
>>
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plp626

回复 11# JooKin


那先用这个代码理解

set/a -2/4294967294
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set/a 4294967295是阶段性罢工，原因未明，我这里有时也罢工，你再试试，

plp626

回复 13# JooKin

->set/a -1/2147483647
0
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plp626

回复 15# JooKin
补码；
你别想复杂了，这是d2b的bat代码：

:: d2b.cmd
@call dec2x.cmd 2 32 %1 %2
@if %2.==. echo %$%
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:: dec2x.cmd
@ECHO %#debug% off
:d2x <进制=2 8 16> <多少位> <数字> <返回>
SETLOCAL ENABLEDELAYEDEXPANSION
set /a "p=%1-1,x=(p-1)/3+^!(%1&16),d=%3,lp=%2"
set m=0123456789ABCDEF&set h=
for /L %%: in (1,1,%lp%)do set/a"t=d&p,d>>=x"&Set h=$m:~!t!,1$!h!
for %%a in ("%h:$=!%")do endlocal&Set $%4=%%~a
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附带两个外部命令：

:: d2h.cmd
@call dec2x 16 8 %1 %2
@if %2.==. echo %$%
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:: d2o.cmd
@call dec2x 8 11 %1 %2
@if %2.==. echo %$%
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