[文本处理] 批处理怎样查找第二次出现的字串并替换为换行？

@echo off
(for /F "delims=" %%a in (1.txt) do (set a=%%a
setlocal enabledelayedexpansion
set "a=!a:<a herf=&echo.#a herf=!"&call:a "!a!"
Endlocal))>2.txt
(for /F "delims=" %%a in (2.txt) do (set a=%%a
setlocal enabledelayedexpansion
set "a=!a:#=<!"&echo.!a!
Endlocal))>1.txt
del 2.txt&exit
:a
echo.%~1
复制代码

sed -i -r "s/(.)(<a herf)/\1\n\2/g" 1.txt
复制代码

@echo off&setlocal enabledelayedexpansion
for /f "delims=" %%i in (a.txt) do call :out "%%i"
pause   
:out
set "v=%~1"
:r
for /f "tokens=1* delims=<" %%i in ("!v!") do (
    echo ^<%%i
    if "%%j" neq "" set "v=%%j"&goto :r
)
复制代码

@echo off&setlocal enabledelayedexpansion
set hh=^


(for /f "delims=" %%a in (a.txt) do (
	set tmp=%%a
	for %%b in ("!hh!") do echo !tmp:^<a herf=%%~b^<a herf!
                rem 换行符必须绕过对语句进行划分的预处理阶段，所以需要开启变量延迟，并通过for实现嵌套
))>tmp
::将所有“<”替换为“换行<”
(for /f "delims=" %%a in (tmp) do echo %%a)>a.txt
::去除多余空行
复制代码