[数值计算] [已解决]批处理如何生成超过5位数的指定范围内的随机数

@echo off & setlocal enableDelayedExpansion
mode 80,2000
for /L %%a in (1 1 1000) do (
    set /a "t=1088000 + (1!random:~-2!!random:~-4!-1000000) %% (498000-88000+1)"
    echo;!t:~-6!
)

pause
exit /b
复制代码

@echo off&setlocal enabledelayedexpansion
rem 拆分拼接(8,8000)~(8,9999);(9,0000)~(9,9999);……(48,0000)~(48,9999);(49,0000)~(49,8000)
(for /l %%a in (1 1 1000) do (
    set /a a=8+!random!%%42&rem 8~49
    if !a! equ 8 (
        set /a b=8000+!random!%%2000&rem 8000~9999
        echo;!a!!b!
    ) else (
        if !a! equ 49 (
            set /a b=10000+!random!%%8001&rem 10000~18000
        ) else (
            set /a b=10000+!random!%%10000&rem 10000~19999
        )
        echo;!a!!b:~1!
    )
))>result.txt
pause
复制代码

@echo off
set min=88000
set max=498000
for /f "delims=" %%a in ('mshta "javascript:(new ActiveXObject('Scripting.Filesystemobject')).GetStandardStream(1).Write(Math.floor(Math.random()*(%max%-%min%+1)+%min%));close()"') do echo;%%a
pause
复制代码

rem win7及以上系统运行
powershell -c "get-random -min 88000 -max 498001"
pause
复制代码

@echo off&setlocal enabledelayedexpansion
REM 设置随机数位数
set BITS=9
for /l %%i in (1,1,200) do (
	set "s=$"
	for /l %%i in (1,1,!BITS!) do (
		set/a "r=!random!%%10"&set "s=!s!!r!"
	)
	set/p=!s!, <NUL
	set/a "n=%%i%%5"
	if !n! equ 0 (echo;)
)
pause
复制代码