[问题求助] sed 如何提取关键字后面的第一对引号中的内容

sed  "s/\(abc\"[0-9a-z]*\"\)/\n\1\n/g" 1.txt | sed -n "/abc\"[0-9a-z]*\"/ s/.*\"\(.*\)\"/\1/p" | sed ":a;N;$!ba;s/\n/ /g"
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sed -n "s/abc\x22/\n/g; s/\x22[^\n]*//g; s/[^\n]*//; p"
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Dim vbstr, rgstr
vbstr = "xxx""abcx""xabc""1""xx""xxx""abc""2""abc""3abc3""xx""x"
Set regex = New RegExp
regex.Global = True
regex.IgnoreCase = True
regex.Pattern = ".*?abc\x22(.*?)\x22"
For Each match In regex.Execute(vbstr)
  rgstr = rgstr & match.Submatches(0)
next
Set regex = Nothing
MsgBox rgstr
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Dim vbstr, rgstr
vbstr = "strxxx""abcx""xabc""1""xFFF""A""xxFFFx""xxx""abc""2""xxFFF""B""xxabc""3abc3""xx""x""FFF""C""xxxFFF"
Set regex = New RegExp
regex.Global = True
regex.IgnoreCase = True
regex.Pattern = ".*?abc\x22(.*?)\x22.*?fff\x22(.*?)\x22"
For Each match In regex.Execute(vbstr)
  rgstr = rgstr & match.Submatches(0) & Chr(9) & match.Submatches(1) & vbCrLf
next
Set regex = Nothing
MsgBox rgstr
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