批处理如何批量修改/替换文件名中指定位置的字符串/字段？

generalzzy

各位专家，我每天收到一堆文件，如下，我需要批量将其中第7/8位的85统一改为50，其他不变，烦请指教

A_HTXA85ECMG170000_C_BABJ_20150717054106_04898.bin.nc
A_HTXA85ECMG171200_C_BABJ_20150717174106_84381.bin.nc
A_HTXE85ECMG170000_C_BABJ_20150717055305_07583.bin.nc
A_HTXE85ECMG171200_C_BABJ_20150717175312_89005.bin.nc
A_HTXI85ECMG170000_C_BABJ_20150717060020_10635.bin.nc
A_HTXI85ECMG171200_C_BABJ_20150717180011_91104.bin.nc
A_HTXK85ECMG170000_C_BABJ_20150717060706_13269.bin.nc
A_HTXK85ECMG171200_C_BABJ_20150717180735_94047.bin.nc
A_HTXM85ECMG170000_C_BABJ_20150717061405_15513.bin.nc
A_HTXM85ECMG171200_C_BABJ_20150717181406_95506.bin.nc
A_HTXO85ECMG170000_C_BABJ_20150717062106_17715.bin.nc
A_HTXO85ECMG171200_C_BABJ_20150717182105_97141.bin.nc
A_HTXQ85ECMG170000_C_BABJ_20150717062806_20599.bin.nc
A_HTXQ85ECMG171200_C_BABJ_20150717182805_05968.bin.nc
A_HTXS85ECMG170000_C_BABJ_20150717063605_24542.bin.nc
A_HTXS85ECMG171200_C_BABJ_20150717183521_08242.bin.nc
A_HTXT85ECMG170000_C_BABJ_20150717065615_35844.bin.nc
A_HTXT85ECMG171200_C_BABJ_20150717185639_11486.bin.nc
A_HTXW85ECMG170000_C_BABJ_20150717064233_27607.bin.nc
A_HTXW85ECMG171200_C_BABJ_20150717184232_09591.bin.nc
A_HTXY85ECMG170000_C_BABJ_20150717064905_32009.bin.nc
A_HTXY85ECMG171200_C_BABJ_20150717184921_10859.bin.nc

pcl_test

举个栗子

1. @set "name=A_HTXA85ECMG170000_C_BABJ_20150717054106_04898.bin.nc"
   
2. @echo %name:~,6%50%name:~8%
   
3. @pause

复制代码

generalzzy

多谢多谢，我想了好半天，你这么快做出了了，赞！！

gawk

1. @echo off
   
2. setlocal enabledelayedexpansion
   
3. for /f %%i in ('dir /b /a-d ^| findstr "^......85"') do (
   
4.     set "OldName=%%i"
   
5.     set "NewName=!OldName:~,6!50!OldName:~8!"
   
6.     ren "!OldName!" "!NewName!"
   
7. )

复制代码

jrx401

这个没看懂