[已解决]批处理如何导出TXT文件中包含某字词的行？

yaua

http://www.bathome.net/viewthread.php?from=notice&tid=12715
源代码在这个帖子中，但试验一个txt，发现导出的行不完整
比如原始txt为

1. (005321) 8/6/2011 14:07:48 PM - (not logged in) (125.43.38.191)> 331 Password required for anonymous
   
2. (005321) 8/6/2011 14:07:51 PM - (not logged in) (125.43.38.191)> PASS *******
   
3. (005321) 8/6/2011 14:07:51 PM - (not logged in) (125.43.38.191)> 530 Login or password incorrect!
   
4. (005321) 8/6/2011 14:07:51 PM - (not logged in) (125.43.38.191)> QUIT
   
5. (005321) 8/6/2011 14:07:51 PM - (not logged in) (125.43.38.191)> 221 Goodbye
   
6. (005321) 8/6/2011 14:07:51 PM - (not logged in) (125.43.38.191)> disconnected.
   
7. (005322) 8/6/2011 14:08:08 PM - (not logged in) (125.43.38.191)> Connected, sending welcome message...
   
8. (005322) 8/6/2011 14:08:08 PM - (not logged in) (125.43.38.191)> 220-FileZilla Server version 0.9.39 beta
   
9. (005322) 8/6/2011 14:08:08 PM - (not logged in) (125.43.38.191)> 220-written by Tim Kosse (Tim.Kosse@gmx.de)
   
10. (005322) 8/6/2011 14:08:08 PM - (not logged in) (125.43.38.191)> 220 Please visit http://sourceforge.net/projects/filezilla/
    
11. (005322) 8/6/2011 14:08:09 PM - (not logged in) (125.43.38.191)> USER anonymous
    
12. (005322) 8/6/2011 14:08:09 PM - (not logged in) (125.43.38.191)> 331 Password required for anonymous
    
13. (005322) 8/6/2011 14:08:09 PM - (not logged in) (125.43.38.191)> PASS *******
    
14. (005322) 8/6/2011 14:08:09 PM - (not logged in) (125.43.38.191)> 421 Temporarily banned for too many failed login attempts
    
15. (005322) 8/6/2011 14:08:09 PM - (not logged in) (125.43.38.191)> disconnected.
    

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使用代码为

1. 
   
2. @echo off
   
3. set "str=220"
   
4. (for /f "tokens=1* delims=:" %%a in ('findstr "%str%" "FileZilla Server.log"') do (
   
5.     echo,%%b
   
6. ))>111.log
   

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导出的内容为

1. 
   
2. 08:08 PM - (not logged in) (125.43.38.191)> 220-FileZilla Server version 0.9.39 beta
   
3. 08:08 PM - (not logged in) (125.43.38.191)> 220-written by Tim Kosse (Tim.Kosse@gmx.de)
   
4. 08:08 PM - (not logged in) (125.43.38.191)> 220 Please visit http://sourceforge.net/projects/filezilla/
   

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似乎前面的日期并没有完整导出，是何原因
还有个问题，要是查找的字符不知一个，比如 220 或 not 两个关键词，又该如何修改代码

601997526

"tokens=1* delims=:"这一句改下就行了

1. 
   
2. @echo off
   
3. set "str=220 not"
   
4. (for /f "delims=" %%a in ('findstr "%str%" "FileZilla Server.log"') do (
   
5.     echo,%%a
   
6. ))>111.log

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也可以改为"tokens=* delims=:"
要不就在findstr后面加上 /n
要查找多个关键字就直接在set str=这里加上关键字和一个空格就行了

yaua

如果查找的关键字中含有空格呢

CUer

回复 4# yaua

1. findstr /c:"abc def"

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yaua

关键字不止一个，且其中一个含有空格。
比如关键字 "a b" 和 "c"

hanyeguxing

1. findstr /c:"a b" /c:"c"

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